17x^2+26x-120=0

Solution for 17x^2+26x-120=0 equation:

17x^2+26x-120=0

a = 17; b = 26; c = -120;
Δ = b2-4ac
Δ = 262-4·17·(-120)
Δ = 8836
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{8836}=94$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-94}{2*17}=\frac{-120}{34}
=-3+9/17
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+94}{2*17}=\frac{68}{34}
=2
$